[blax123]

IMHO general idea is that there is 1 bit for each CC-ID and all of them are sequential.

AFAIK SOS failure is CC-ID 299.

Each group has 8 bytes so 64 (= 8 * 8) bits total.

299 / 64 = 4.xxx so it's 5th group (as groups are counted from 1: 4 + 1 = 5).

299 - 64 * 4 = 43 so it's 43rd bit in 5th group.

43 / 8 = 5.xxx so it's 5th byte (as bytes are counted from 0: 5 + 0 = 5).

43 - 5 * 8 = 3 so it's 3rd bit (as bits are also counted from 0)

3rd bit has value of 8 (= 2 ^ 3) so FF - 8 = F7. Well, to be more precise - works when bit WAS SET ONLY. Normally you would do NOT-AND operation which works always. So initial value FF & (~8). ~8 = F7. FF & F7 = F7.

ELEMENTARY!!!

Example for CC-ID 128 (failure left high beam) would mean:

128 / 64 = 2 -> 2+1 = 3 = cc_aktivierung_3
128 - 64 * 2 = 0
0 / 8 = 0th byte
0 / -0 * 8 = 0th bit
FF - 2^0 = assuming default is FF -> - 1 = EF?
FF, FF, FF, FF, FF, FF, FF, FF transform to -> EF, FF, FF, FF, FF, FF, FF, FF ?