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Can Anyone Help me!
14-01-2017, 15:44 PM,
Post: #1
VToyota  Can Anyone Help me!
B8 12 b8 12 b8 12 b8 12 b8 12 b8 12 b8 12 b8 12
b7 12 b7 12 b7 12 b7 12 b7 12 b7 12 b7 12 b7 12
b7 12 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff

b8 12 byte swap to 12b8 > dec = 4792 X 8 = 38336
b7 12 byte swap to 12b7 > dec = 4791 X 9 = 43119
.......................total places = 17.= 81455

I can't able to figure it out why/how we need to split our code into two part (i.e. B812 = 8 byte B7 12 = 9 Byte)

Thank you in advance for helping meinfo

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14-01-2017, 16:54 PM, (This post was last modified: 14-01-2017, 17:30 PM by Clusters.)
Post: #2
RE: Can Anyone Help me!
Because if you didn't you would only be able to count in steps of 17.

All B812 = 81464
All B712 = 81447

16 bytes B812 and one byte B712 = 81463

Also notice the 00 and ff following the mileage bytes, if you don't correct these to match you will get errors.

If it was all b812 (even number) you would make them all 00
If it was all b712 (odd number) you would make them all ff

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14-01-2017, 20:28 PM,
Post: #3
RE: Can Anyone Help me!
(14-01-2017, 16:54 PM)clusters Wrote:  Because if you didn't you would only be able to count in steps of 17.

All B812 = 81464
All B712 = 81447

16 bytes B812 and one byte B712 = 81463

Also notice the 00 and ff following the mileage bytes, if you don't correct these to match you will get errors.

If it was all b812 (even number) you would make them all 00
If it was all b712 (odd number) you would make them all ff

Thank you for your help and guidance once again, now i am working 24c16 hopefully decode that soon. read

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