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Can Anyone Help me!
14-01-2017, 15:44 PM,
Post: #1
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Can Anyone Help me!
B8 12 b8 12 b8 12 b8 12 b8 12 b8 12 b8 12 b8 12
b7 12 b7 12 b7 12 b7 12 b7 12 b7 12 b7 12 b7 12 b7 12 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff b8 12 byte swap to 12b8 > dec = 4792 X 8 = 38336 b7 12 byte swap to 12b7 > dec = 4791 X 9 = 43119 .......................total places = 17.= 81455 I can't able to figure it out why/how we need to split our code into two part (i.e. B812 = 8 byte B7 12 = 9 Byte) Thank you in advance for helping me My post helps you? Please Hit and buttons.
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14-01-2017, 16:54 PM,
(This post was last modified: 14-01-2017, 17:30 PM by Clusters.)
Post: #2
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RE: Can Anyone Help me!
Because if you didn't you would only be able to count in steps of 17.
All B812 = 81464 All B712 = 81447 16 bytes B812 and one byte B712 = 81463 Also notice the 00 and ff following the mileage bytes, if you don't correct these to match you will get errors. If it was all b812 (even number) you would make them all 00 If it was all b712 (odd number) you would make them all ff If someone took the time to help you, the least you can do is take a few seconds and press two buttons!
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14-01-2017, 20:28 PM,
Post: #3
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RE: Can Anyone Help me!
(14-01-2017, 16:54 PM)clusters Wrote: Because if you didn't you would only be able to count in steps of 17. Thank you for your help and guidance once again, now i am working 24c16 hopefully decode that soon. My post helps you? Please Hit and buttons.
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