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Why I do not understand the microprocessor chargers? The process which you described is not constant voltage, but instead current limiting charger which is better design. And that does not make my other statements invalid. And that process is exactly what is shown in the picture I attached.

P.S. And you really don't want "And as it drops to 4A then the charger will turn off to standby mode" during programming, as it will cause voltage drop spike and that is exactly what kills units during programming. Not 14.8V vs 13.8V but constant voltage.