[int]

...

would this do the job?

Correct the post in first place, links only in attachments 

About your questions:

For coding: yes
For programing: no

You have like 6 pages of post ppl recomending what to use, choose one If you want to have quality tools then it's going to hurt your wallet

Is it really true that a NOCO GB* would be ok for coding? Thought it was only for giving the car a 'boost' when the battery was dead?

ALSO, has anyone used a Powermax PM4-100LK? Considering buying this (available on Amazon) but wanted some feedback first

[XuLeTZ]

Diagnosis on Saturday BMW M5 F11 first several minutes 67A
but I only set it to 13.8V,
  (ista from icom next the original showed 13.6V)
probably at 14.4V it would be over 80A
after a few hours the ignition dropped to 35A / 13.8V
Very good facilities,
Gysflash 100-12-HF

Increasing the voltage will lower the amps. Lowering the voltage will increase the amps. that`s how is working. So best to keep it at 13.8V with 67A. If you need higher amps, lower the voltage.
Any supply has written on the label. 220V - 1200W - 12V = 100AMPS (this is an example, like connecting it to 220V at your home socket)
So that means it will produce 100Amps at 12V. Now, if you increase the voltage, use the simple math. Wattage divided by voltage equals amps. Eg 1200W/12V=100Amps
let`s increase it to 13.8V - 1200W/13.8V=87A (86.95652173913043)
So don`t increase the voltage if you need more amps

[Kentener]

Diagnosis on Saturday BMW M5 F11 first several minutes 67A
but I only set it to 13.8V,
  (ista from icom next the original showed 13.6V)
probably at 14.4V it would be over 80A
after a few hours the ignition dropped to 35A / 13.8V
Very good facilities,
Gysflash 100-12-HF

Increasing the voltage will lower the amps. Lowering the voltage will increase the amps. that`s how is working. So best to keep it at 13.8V with 67A. If you need higher amps, lower the voltage.
Any supply has written on the label. 220V - 1200W - 12V = 100AMPS (this is an example, like connecting it to 220V at your home socket)
So that means it will produce 100Amps at 12V. Now, if you increase the voltage, use the simple math. Wattage divided by voltage equals amps. Eg 1200W/12V=100Amps
let`s increase it to 13.8V - 1200W/13.8V=87A (86.95652173913043)
So don`t increase the voltage if you need more amps

Sorry, but that's nonsense!

[ir655]

[quote pid='553154' dateline='1662018730']



Increasing the voltage will lower the amps. Lowering the voltage will increase the amps. that`s how is working. So best to keep it at 13.8V with 67A. If you need higher amps, lower the voltage.
Any supply has written on the label. 220V - 1200W - 12V = 100AMPS (this is an example, like connecting it to 220V at your home socket)
So that means it will produce 100Amps at 12V. Now, if you increase the voltage, use the simple math. Wattage divided by voltage equals amps. Eg 1200W/12V=100Amps
let`s increase it to 13.8V - 1200W/13.8V=87A (86.95652173913043)
So don`t increase the voltage if you need more amps

Sorry, but that's nonsense!
[/quote]

How come the formula (w)÷(V)=A doesnt apply? 

Cant be nonsense then. Increase voltage, amps drop.I am not an electrician so I could be missing something.

[int]

ALSO, has anyone used a Powermax PM4-100LK? Considering buying this (available on Amazon) but wanted some feedback first

Just picked up the Powermax PM4-100LK today - can someone recommend cables to use for these? Guessing the ones with my NOCO GB70 aren't thick enough (< gauge)

[Kentener]

Sorry, but there really is some incredible crap being said here. Of course, a charger does not always deliver the same power. If a rating plate states a rated power or a rated current, these are possible maximum values.

When the voltage rises, the current rises and so does the power.

[slackers]

Plus one other thing to add - if you keep the supply at 12V, ISTA won't be very happy as it wants to see a minimum of 13.2V IIRC correctly.

[XuLeTZ]

[quote pid='553154' dateline='1662018730']



Increasing the voltage will lower the amps. Lowering the voltage will increase the amps. that`s how is working. So best to keep it at 13.8V with 67A. If you need higher amps, lower the voltage.
Any supply has written on the label. 220V - 1200W - 12V = 100AMPS (this is an example, like connecting it to 220V at your home socket)
So that means it will produce 100Amps at 12V. Now, if you increase the voltage, use the simple math. Wattage divided by voltage equals amps. Eg 1200W/12V=100Amps
let`s increase it to 13.8V - 1200W/13.8V=87A (86.95652173913043)
So don`t increase the voltage if you need more amps

Sorry, but that's nonsense!

How come the formula (w)÷(V)=A doesnt apply? 

Cant be nonsense then. Increase voltage, amps drop.I am not an electrician so I could be missing something.
[/quote]

He has no clue he thinks the amps are going up if you go up with the voltage as well he just said nonsense, he didn`t say why. so yeah ... nonsense ... 

Literally on my PSU says:
Input 200V-240V
OUTPUT 1200W
12V 100A
This being said, the formula applies: W÷V=A
So literally nonsense

[ir655]

When the voltage rises, the current rises and so does the power.

Aha I see you are staring blindly at a formula without applying it to the real world example of a charger or battery maintainer. As you can see below, the formula the whole world uses to calculate Power (watts).

P = V * I

P = Power (watts)
V = voltage (volts)
I = current (amps)

1200W charger at 12V will produce 100A in theory then. If you increase voltage as you say, current must drop to not exceed 1200W max output of the charger. 

P in the case of chargers and battery maintainers is a fixed value (whatever the sticker says on your charger). 

You forget that the Power output has a cap in this case so you cant just assume that if voltage increases, the rest increases also when applied to real world applications such as battery maintainers and chargers.

I can still be wrong though! I am not an electrician, just an aircraft technician that occasionally work on electrical components of commercial aircraft. In that case I apologize if I am spreading misinformation to members.

[pupu144]

When the voltage rises, the current rises and so does the power.

Aha I see you are staring blindly at a formula without applying it to the real world example of a charger or battery maintainer. As you can see below, the formula the whole world uses to calculate Power (watts).

P = V * I

P = Power (watts)
V = voltage (volts)
I = current (amps)

1200W charger at 12V will produce 100A in theory then. If you increase voltage as you say, current must drop to not exceed 1200W max output of the charger. 

P in the case of chargers and battery maintainers is a fixed value (whatever the sticker says on your charger). 

You forget that the Power output has a cap in this case so you cant just assume that if voltage increases, the rest increases also when applied to real world applications such as battery maintainers and chargers.

I can still be wrong though! I am not an electrician, just an aircraft technician that occasionally work on electrical components of commercial aircraft. In that case I apologize if I am spreading misinformation to members.

It is true.. It's basic electrical engineering..

There are also various posts over the Internet with the testing of said server PSU builds with current load test, which confirms that output current decreases with voltage increase.

Also, sudden current spikes would drop the voltage anyway - so it stays true. There is no infinite energy source available for now, so output power is constant


It might be true for some dedicated battery maintainers which have predefined voltage output levels - but that only means that they cap their output at lower output voltages, not that higher voltage = bigger amps.